Problema Solution
Find the two consecutive even integers such that twice the smaller exceeds the larger by 18
Answer provided by our tutors
let '2n' represent the first even number, then '2n+2' represents the next consecutive even number
2(2n) = 2n+2 + 18
solving for 'n' we have n=10
2*10 = 20
2*10 + 2 = 22
the numbers are 20 and 22