Problema Solution
five times the first three consecutive even integers is 4 less than twice the sum of the second and third
Answer provided by our tutors
we interpret "five times the first three consecutive" to mean "five times the sum of first three consecutive"
let '2n' represent the first even integer, then '2n+2' and '2n+4' represent the second and third consecutive even integers
5(2n+2n+2+2n+4) = 2(2n+2+2n+4)-4
solving for 'n' we have n=-1
2*n = -2
the three consecutive even numbers are -2, 0 and 2