Problema Solution
What is the equation of the line that has a slope of 3 and that passes through the point (-1, 5)?
Answer provided by our tutors
The slope or gradient of a line is a number that describes both the direction and the steepness of the line. Slope is often denoted by the letter m. In our case slope m = 3.
The equation of a line is: y = k*x + b, k is coefficient, b is the y-intercept of the line
Since y is a linear function of x , the coefficient of x is the slope of the line that is k = m . Therefore, the equation of the line is given in the form:
y = m * x + b
Since m = 3 we have y = 3*x + b
We need to find b!
Since this line y = 3*x + b is passing trough (-1, 5) if we put x = -1 and y = 5 we get:
5 = 3 * (-1) + b
b - 3 = 5
b = 5 + 3
b = 8
Finally, the equation of the line is y = 3x + 8.