Problema Solution

What is the equation of the line that has a slope of 3 and that passes through the point (-1, 5)?

Answer provided by our tutors

The slope or gradient of a line is a number that describes both the direction and the steepness of the line. Slope is often denoted by the letter m. In our case slope m = 3.


The equation of a line is: y = k*x + b, k is coefficient, b is the y-intercept of the line


Since y is a linear function of x , the coefficient of x is the slope of the line that is k = m . Therefore, the equation of the line is given in the form:


y = m * x + b


Since m = 3 we have y = 3*x + b


We need to find b!


Since this line y = 3*x + b is passing trough (-1, 5) if we put x = -1 and y = 5 we get:


5 = 3 * (-1) + b

b - 3 = 5

b = 5 + 3


b = 8


Finally, the equation of the line is y = 3x + 8.