Problema Solution

if amy has 15 coins totaling $2.70, and the coins are quaters and dimes, how many of each coins does she have?

Answer provided by our tutors

Let 'x' be the number of quarters and 'y' be the number of dimes. Also x and y are non-negative integer numbers. We need to find x and y.


We know that

1 quarter = 25 cents

1 dime = 10 cents

$1 = 100 cents


Follwoing the conditions we have


x + y = 15 => x = 15 - y

25 x + 10 y = 270 ( since $2.70 = 2.70 * 100 cents = 270 cents)


By replacing x from the first equation in the second we have


25 (15 - y) + 10 y = 270

375 - 25 y + 10 y = 270

25 y - 10 y = 375 - 270

15 y = 105

y= 105 / 15


y = 7 dimes


x = 15 - y

x = 15 - 7


x = 8 quarters


Amy has 8 quarters and 7 dimes.