Problema Solution
Find two consecutive even integers such that four times the first is three times the second. (Enter your answers as a comma-separated list.)
Answer provided by our tutors
let '2n' represent the first even integer, then '2n+2' represents the next consecutive even integer
4(2n) = 3(2n+2)
solving for 'n' we have n=3
2*3 = 6
2*3 + 2 = 8
the numbers are 6 and 8
the solution set is {6, 8}