we assume these are consecutive odd integers, otherwise there is not enough information to solve this problem

let '2n+1' represent the first odd integer, then '2n+3' and '2n+5' represents the next two consecutive odd integers

the sum of the first two integers is five more than the third integer:

(2n+1)+(2n+3) = (2n+5) + 5

4n + 4 = 2n + 10

2n = 6

n = 3

2*3+1 = 7

the integers are 7, 9 and 11