Problema Solution
A 1165 kg automobile is pulled by a horizontal tow line with a net force of 844 N.
What is the acceleration of the auto? (Neglect friction.)
Answer provided by our tutors
F=ma
844 = 1165a
a = 844/1165 = 0.724 N/kg
N = kg*(m/s^2)
kg*(m/s^2)/kg = m/s^2
acceleration is 0.725 m/s^2