Problema Solution
the value of a Jefferson coin is 5/4 the value of a different coin. together they are 72$ in value. what is the vale of each coin.
Answer provided by our tutors
Let 'j' and 'd' stand for the respective prices of the Jefferson coin and the different coin. From the given information, we can write:
j=(5/4)d
j+d=72
Using Algebrator to solve for 'd' and 'j', we get:
d=$32
j=$40