Problema Solution
Isosceles triangle ABC has vertices A(2,5), B(10,3)and C(2,1). What is the equations of the perpendicular bisector of AC?
Answer provided by our tutors
SLOPE OF AC= 1-5/2-2= INFINTY
SLOPE OF LINE PREPENDICUALR TO AC
= 1/SLOPE OF AC= 0
LINE PASS THROUGH A= (2,5) AND WITH SLOPE ZERO
Y- 5= 0(X-2)
Y=5
EQUATION OF the perpendicular bisector of AC