Problema Solution
A Chemist has to make 80-liters of 15.5% Alcohol solution from mixing a 32% solution and a 10% solution. How many liters of each type are mixed?
Answer provided by our tutors
Let
'x' = liters of 32% solution
'y' = liters of 10% solution
Then we have
x + y = 80 (because x liters + y liters = total liters)
0.32x + 0.10y = 0.155*80 (because %(liters) + %(liters) = %(total liters))
We need to find the solution of the following system
x + y = 80
0.32x + 0.10y = 0.155*80 multiply both sides by 100
x = 80 - y
32x + 10y = 1240
x = 20
y = 60
We need 20 liters of 32% solution and 60 liters of 10% solution.