Problema Solution
The length of a rectangular piece of steel in a bridge is 3 meters less than double the width. The perimeter of the piece of steel is 42 meters. Find the length of the piece of steel. Find the width of the piece of steel.
Answer provided by our tutors
Let
l = length of the rectangular piece of steep
w = width of the rectangular piece of steep
l = 2*w - 3 (the length is 3 meters less than double the width)
The Perimeter of the rectange is 2 times the (width + length) that is
2 (w + l) = 42
The solutions of the system
l = 2*w - 3
2 (w + l) = 42
are
l = 13 meters
w = 8 meters
The piece of steel has 13 meters in length and 8 meters width.