Problema Solution
in the 2008 mlb season tampa bay won 33 fewer than twice as many games they lost. they played 162 regular season games. how many wins and loses did the team have
Answer provided by our tutors
Let
'x' be the number of games won
'y' be the number of games lost
x = 2*y - 33 (tampa bay won 33 fewer than twice as many games they lost)
x + y = 162 (they played 162 regular season games)
If we solve the system we get
x = 97
y = 65
The team had 97 wins and 65 loses.