Problema Solution
Anita scored 18 less than Miguel, Cheri's score was 16 less than twice Anita's. Cheri outscored jake by 21. The total scored by all four kids is 529 what was the final score by each kid?
Answer provided by our tutors
Let
x = score of Anita
y = score of Miguel
z = score of Cheri
t = score of Jake
x = y - 18 (Anita scored 18 less than Miguel)
z = 2*x - 16 (Cheri's score was 16 less than twice Anita's)
z = t + 21 (Cheri outscored Jake by 21)
x + y + x + t = 529 (The total scored by all four kids is 529)
If we solve this system of equations we find the results
x = 548/5 = 109.6 is the score of Anita
y = 638/5 = 127.6 is the score of Miguel
z = 1016/5 = 203.2 is the score of Cheri
t = 911/5 = 182.2 is the score of Jake