Problema Solution
how many mL of a 4g/L stock is needed to prepare 160 mL of a 1 g/L Solution
Answer provided by our tutors
concentration = pure-solution/total-volume
we want to express every uniformly, so convert mL to L
160 mL*1L/10^3mL = 0.16L
let 'x' represent the amount of pure solution required, then we want
1 g/L = x/0.16L
0.16g = x
we want enough of the 4g/L stock to given us 0.16g of pure solution:
0.16g/(4g/L) = 0.04L = 40mL
we need 40mL of the 4g/L stock
concentration = pure-solution/total-volume
we want to express every uniformly, so convert mL to L
160 mL*1L/10^3mL = 0.16L
let 'x' represent the amount of pure solution required, then we want
1 g/L = x/0.16L
0.16g = x
we want enough of the 4g/L stock to given us 0.16g of pure solution:
0.16g/(4g/L) = 0.04L = 40mL
we need 40mL of the 4g/L stock