Problema Solution

A circle of radius 10cm is divided into two pieces using a straight line of length 15cm. Calculate the area of the smallest piece.

Answer provided by our tutors

A circular segment is enclosed between a secant/chord and the arc whose endpoints equal the chord's.


In our case we need to find the area of the circular segment with secant/chord of length 15 cm and radii 10 cm.


The area of the circular segment is equal to the area of the circular sector minus the area of the triangular portion.


Area of Segment = ½ × (θ - sin θ) × r^2 (when θ is in radians)


we have r = 10 cm, we need to find θ.


θ = the angle above the chords with length 15 cm. Using the definition for sinus we find


sin(θ/2) = (c/2) / r = c/2*r = 15 / 20 = 7.5 /10


θ = 2 arcsin (7.5 /10)


θ = 2*0.848 = 1.696 rad


sin θ = 0.992


Area of Segment = ½ × (θ - sin θ) × r^2 = ½ × (1.696 - 0.992) × 10^2


Area of Segment = 35.2 cm^2.