Problema Solution
How many liters of pure acid should be mixed with 10 L of 60% acid to prepare a mixture of 75% acid?
Answer provided by our tutors
Let 'x' represent the amount of pure acid added.
60% of 10 + 100% of x = 75% of (10 + x)
0.6*10 + x = 0.75(10 + x)
Simplify and Solve
x = 6 l of pure acid should be added to prepare a mixture of 75% acid.