Problema Solution
A chemist needs to mix a 10% sodium iodine solution with a 60% sodium iodine solution to obtain 50 milliliters of a 30% sodium iodine solution. How many milliliters of the 10% and 60% solutions should be mixed?
Answer provided by our tutors
let
x = milliliters of the 10% sodium iodine solution
y = milliliters of the 60% sodium iodine solution
we need to make 50 ml solution thus
x + y = 50
mix a 10% sodium iodine solution with a 60% sodium iodine solution to obtain 50 milliliters of a 30% sodium iodine solution
0.1*x + 0.6*y = 0.3*50
by solving the system of equations
x + y = 50
0.1*x + 0.6*y = 0.3*50
we find
x = 30 ml
y = 20 ml
We need to mix 30 ml of 10% sodium iodine solution and 20 ml of 60% sodium iodine solution.