Problema Solution
Chemistry. E-chem testing has a solution that is 80% base and another that is 30% base. A technician needs 150 L of a solution that is 62% base. The 150 L will be prepared by mixing the two solutions on hand. How much of each should be used.
Answer provided by our tutors
let
x = the L of the 80% base solution or (80/100)*x = 0.8*x
y = the L of the 30% base solution 0r (30/100)*x = 0.3*x
the two solutions mixed make 150 l of 62% base that is
x + y = 150
0.8*x + 0.3*y = 0.62*150
by solving this system of equations we find
x = 96 L
y = 54 L
We should mix 96 L of the 80% base solution and 54 L of the 30% base solution.