Problema Solution
How much of a 50% alcohol solution should we mix with 10 gallons of a 35% solution to get a 40% solution?
Answer provided by our tutors
let
x = gallons of 50% alcohol solution
y = 10 gallons of 35% solution
by mixing x and y we get x + y gallons of a 40% solutions
0.5*x + 0.35*10 = 0.40*(x + 10)
by solving this equation we find
x = 5 gallons
we need 5 gallons of 50% alcohol solution.