Problema Solution

electric light bulbs can be packed into boxes of 16 or 24. how can 232 bulbs be packed into full boxes only? Find two possible ways.

Answer provided by our tutors

let


x = the number of 16 bulb boxes

y = the number of 24 bulb boxes


the bulbs from x + the bulbs from y = total number of bulbs


16*x + 24*y = 232 divide both sides by 8


2*x + 3*y = 29


since y >=0 we have 2*x = 29 - 3*y <=29 that is x<=29/2


x < = 14


also notice that x is not divisible by 3 (otherwise if x is divisible by 3 the left side of the equation 2*x + 3*y = 29 will be divisible by 3 while the right side 29 is not divisible by 3)


If x = 1 then y = (29 - 2)/3 = 9 is one solution x=1, y=9


If x = 2 then y = (29 - 4)/3 is not integer thus is not a solution


If x = 4 then y = (29 - 8)/3 = 7 is second solution x=4, y=7


We found 2 possible ways of packing:


One way: 1 box of 16 bulbs & 9 boxes of 24 bulbs.


Second way: 4 boxes of 16 bulbs & 7 boxes of 24 bulbs.