Problema Solution

find two consecutive positive integers such that the sum of their square is 313

Answer provided by our tutors

we interpret "the sum of their square is 313" to mean "the sum of their squares is 313"


let 'n' represent the first positive integer, then 'n+1' represents the second integer


the sum of their squares is 313:

n^2 + (n+1)^2 = 313

solving for 'n' we have a positive value of n=12


12+1 = 13


the numbers are 12 and 13