Problema Solution
find two consecutive positive integers such that the sum of their square is 313
Answer provided by our tutors
we interpret "the sum of their square is 313" to mean "the sum of their squares is 313"
let 'n' represent the first positive integer, then 'n+1' represents the second integer
the sum of their squares is 313:
n^2 + (n+1)^2 = 313
solving for 'n' we have a positive value of n=12
12+1 = 13
the numbers are 12 and 13