Problema Solution
Fifteen liters of fuel containing 3.2% oil is available for a certain two-cycle engine. This fuel is to be used for another engine requiring a 5.5%.
Answer provided by our tutors
we are solving this under the assumption that pure oil is being added to the 3.2% solution, but this needs to be specified in the problem statement!
let 'x' represent the total amount of fuel after adding in some 3.2% fuel and let 'y' represent the pre-existing amount of 3.2% fuel
concentration = pure/total
let 'p' represent the amount of pure oil already in the 3.2% fuel:
0.032 = p/y, so p = 0.032y
we want a 5.5% solution:
0.053 = (x+0.032y)/(x+y)
solving for 'x' we have:
x = (21y)/947
x = 0.022y
we need to add approximately 0.22y of pure oil, where 'y' is the amount of existing fuel