Problema Solution
A can of soda at 76 fahrenheit is placed in a refrigerator that maintains a constant temperature of 35 fahrenheit. The temperature of T of the soda t minutes after it is placed in the refrigerator is given by T(t)=35+41e-0.058t. Find the temperature of the soda 15 minutes after it is placed in the refrigerator.(round to the nearest tenth of a degree) . Please show your work.
Answer provided by our tutors
let
D = 35
Ts = 76
t = 15 degrees
e = 2.71828
the temperature is given by the formula
T(t) = 35+41e^(-0.058t)
if we substitute the vale for t=15 we get
T(15) = 35 + 41*2.71828^(-0.058*15)
T(15) = 52.2 Fahrenheit
the temperature after 15 min is 52.2 Fahrenheit.