Problema Solution
find four consecutive even integers so that the sum of the first three is 2 more than twice the fourth
Answer provided by our tutors
the four consecutive integers can be written as
2k - 2, 2k, 2k+2 and 2k + 4, where k is integer
the sum of the first three is 2 more than twice the fourth
2k - 2 + 2k + 2k + 2 = 2*(2k + 4) + 2
6k = 4k + 10
2k = 10
k = 5
2k - 2 = 2*5 - 2 = 8
The four consecutive even integers are 8, 10, 12 and 14.