Problema Solution
how many liters of water must be added to 7 liters of 20% acid solution to obtain 10% solution?
Answer provided by our tutors
let
x = the liters of water that must be added
note that the water is 0% acid solution
0% of acid is x l water + 20% acid in 7 l of water = 10% acid in (x + 7) l solution
0*x + 0.2*7 = 0.1*(x + 7)
0.1*x + 0.7 = 1.4
x = (1.4 - 0.7)/0.1
x = 7 l
we must add 7 liters of water.