Problema Solution
find four consecutive odd numbers such that the product of the first and third will be 64 less than the product of the 2nd and 4th
Answer provided by our tutors
Every odd number can be written in a form 2k +1, where k is integer.
let the four consecutive odd numbers be
2k - 1, 2k + 1, 2k + 3, 2k + 5, where k is integer
the product of the first and third will be 64 less than the product of the 2nd and 4th
(2k - 1)(2k + 3) = (2k + 1)(2k + 5) - 64
multiply and simplify we find
4k - 3 = 12 k - 59
8k = 56
k = 7
2k - 1 = 13
2k + 1 = 15
2k + 3 = 17
2k + 5 = 19
the four consecutive odd numbers are 13, 15, 17 and 19.