Problema Solution

find four consecutive odd numbers such that the product of the first and third will be 64 less than the product of the 2nd and 4th

Answer provided by our tutors

Every odd number can be written in a form 2k +1, where k is integer.


let the four consecutive odd numbers be


2k - 1, 2k + 1, 2k + 3, 2k + 5, where k is integer


the product of the first and third will be 64 less than the product of the 2nd and 4th


(2k - 1)(2k + 3) = (2k + 1)(2k + 5) - 64


multiply and simplify we find


4k - 3 = 12 k - 59


8k = 56


k = 7


2k - 1 = 13

2k + 1 = 15

2k + 3 = 17

2k + 5 = 19


the four consecutive odd numbers are 13, 15, 17 and 19.