Problema Solution
A jet flew at an average speed of 480 mph from point X to point Y. Because of the winds, the jet averaged only 460 mph on the return trip and the return trip took 50 minutes longer. How many hours was the flight from point Y to point X? How far is it from Point Y to point X?
Answer provided by our tutors
let
v1 = 480 mph the speed from X to Y
t1 = the time from X to Y expressed in hours
v2 = 460 mph the speed from Y to X
t2 = the time from Y to X expressed in hours
the return trip took 50 minutes longer and 50 min = 50/60 hours
t2 = t1 + 50/60
t2 = t1 + 5/6
since the distance = avg. speed* time we have
v1*t1 = v2*t2
480*t1 = 460*t2
by solving the system of equations
t2 = t1 + 5/6
480*t1 = 460*t2
we find
t1 = 115/6 hours = 19 hours 10 min
t2 = 20 hours
the flight from Y to X took 20 hours.
the distance = t2*v2 = 20 * 460 = 9200 miles
there are 9,200 miles from Point Y to Point X.