Problema Solution
a picture has a height that is 4/3 its width. It is to be enlarged to have an area of 192 square inches. What will be the dimensions of the enlargement?
Answer provided by our tutors
let
h = height of the enlargement
w = width of the enlargement
a picture has a height that is 4/3 its width
h = (4/3)*w
Area = Height * Width
192 = h*w
h*w = 192
(4/3)*w*w = 192 multiply both sides by 3/4
w^2 = 192*3/4
w^2 = 144
w = 12 in
h = (4/3)*12 = 16 in
the dimensions of the enlargement will be 12 in and 16 in.