Problema Solution
A man is 4 times as old as his son. How old is each now if the sum of their age is 65?
Answer provided by our tutors
let
x = the age of the man
y = the age of his son
a man is 4 times as old as his son
x = 4y
the sum of their age is 65
x + y = 65
by solving the system of equations
x = 4y
x + y = 65
we find
x = 52 years
y = 13 years
the man is 52 years old.
his son is 13 years old.