Problema Solution

the length of a rectangle garden is 9 feet more than it's width. A sidewalk 3 feet wide surrounds the garden covering an area of 450 square feet. What are the dimensions of the garden?

Answer provided by our tutors

let


w = the width of the rectangle garden

l = the length of the rectangle garden


the length of a rectangle garden is 9 feet more than it's width


l = 9 + w


A sidewalk 3 feet wide surrounds the garden covering an area of 450 square feet


(l + 2*3)(w + 2*3) - l*w = 450


(l + 6)(w + 6) - lw = 450


6(l + w) = 414


l + w = 69


by solving the system of equations


l = 9 + w

l + w = 69


we find


l = 39 ft


w = 30 ft


the dimensions of the garden are 39 ft and 30 ft.