Problema Solution
the length of a rectangle garden is 9 feet more than it's width. A sidewalk 3 feet wide surrounds the garden covering an area of 450 square feet. What are the dimensions of the garden?
Answer provided by our tutors
let
w = the width of the rectangle garden
l = the length of the rectangle garden
the length of a rectangle garden is 9 feet more than it's width
l = 9 + w
A sidewalk 3 feet wide surrounds the garden covering an area of 450 square feet
(l + 2*3)(w + 2*3) - l*w = 450
(l + 6)(w + 6) - lw = 450
6(l + w) = 414
l + w = 69
by solving the system of equations
l = 9 + w
l + w = 69
we find
l = 39 ft
w = 30 ft
the dimensions of the garden are 39 ft and 30 ft.