Problema Solution
In a rectangle, the diagonal measures p
130 inches. The length of the rectangle is two inches more
than three times the width. Find the AREA of this rectangle.
Answer provided by our tutors
let
l = length of the rectangle
w = width of the rectangle
d = 130 diagonal
the length of the rectangle is two inches more than three times the width
l = 2 + 3w
by Pythagorean Theorem
w^2 + l^2 = d^2
w^2 + l^2 = 130^2
by solving the system of equations
l = 2 + 3w
w^2 + l^2 = 130^2
we find
l = 123.53 in
w = 40.51 in
the area = width * length
the area = 123.53 * 40.51 = 5004.2 in^2.