Problema Solution

two positive numbers differ by 7 and the sum of their squares is 169. find the numbers.

Answer provided by our tutors

let


x = the first number, x>0

y = the second number, y>0


and without lost of generality we can assume x>y


two positive numbers differ by 7


x - y = 7


the sum of their squares is 169


x^2 + y^2 = 169


by solving the system of equations


x - y = 7

x^2 + y^2 = 169


we find that


x = 12


y = 5


we consider only the positive solutions


the numbers are 12 and 5.