Problema Solution
In a triangle the sum of the angles is 180 degrees. If Angle A is four times Angle B and Angle C is 11 degrees more than twice Angle A. Find the measures of the three angles to the nearest degree.
Answer provided by our tutors
Angle A + Angle B + Angle C = 180
Angle A is four times Angle B
Angle A = 4 * Angle B
Angle C is 11 degrees more than twice Angle A
Angle C = 11 + 2 * Angle A
by solving the system of equations
Angle A + Angle B + Angle C = 180
Angle A = 4 * Angle B
Angle C = 11 + 2 * Angle A
we find
Angle A = 52 degrees
Angle B = 13 degrees
Angle C = 115 degrees