Problema Solution
The perimeter of a rectangle is 200 yards. What are the dimensions of the rectangle if the length is 30 yards more than the width?
Answer provided by our tutors
let
w = width of the rectangle
l = length of the rectangle
P = 2(l + w) is the perimeter formula of rectangle
P = 200 yards
2(l + w) = 200 divide both sides by 2
l + w = 100
the length is 30 yards more than the width
l = w + 30
by solving the system of equations
l + w = 100
l = w + 30
we find
l = 65 yards
w = 35 yards
the dimensions of the rectangle are 35 and 65 yards.