Problema Solution
The volume V of a given mass of gas varies directly as the temperature T and inversely as the pressure P. A measuring device is calibrated to give V=364^3 when T =360degree and P=101lb/in^2. What is the volume on this device when the temperature is 300 degree and the pressure is 25lb/in^2
Answer provided by our tutors
Since the volume V of a given mass of gas varies directly as the temperature T and inversely as the pressure P we can write
V = k*T/P, where k is a constant
using V=364^3 in^3 when T =360degree and P=101lb/in^2 we can find k
k = V*P/T
k = (364^3)*101/360
k = (2^3)*(7^3)*(13^3)*101/(3^2*5)
when T = 300 and P = 25 lb/in^2
V = (2^3)*(7^3)*(13^3)*101*300/(3^2*5*25)
V = 162369431.47 in^3
the volume is 162369431.47 in^3.