For this question, we will use the general exponential growth equation: y=ae^(kt). From the given information we can write:

71=ae^(k3)

93=ae^(k9)

This gives us two equation with two unknowns (a, k). Rearranging, we get:

ln(71)-ln(a)=3k

ln(93)-ln(a)=9k

Subtracting the second equation from the first, we get:

ln(71)-ln(93)=-6k

Solving for 'k', we get:

k=0.01796

We can use this to plug into one of the earlier equation to find 'a':

71=ae^(0.01796*3)

Solving for a, we get:

a=67.28

Therefore, the general equation is:

y=67.28 e^(0.01796 t)