let 'x' and 'y' be the numbers and x>y thus

x = 3y (one number is three times another)

four times the smaller added to five times the greater amount to 133

5x + 4y = 133

by solving the system of equations

x = 3y

5x + 4y = 133

we find

x = 21

y = 7

the numbers are 21 and 7.