Problema Solution
the perimeter of a rectangle is 112 m. the length is 5 m more than twice the width. find the dimensions
Answer provided by our tutors
We can solve this with algebra.
Perimeter = 2 l + 2 w
l = w + 5
Therefore, perimeter = 2 (w + 5) + 2 w
112 = 2 (w + 5) + 2 w
112 = 4w + 10
102 = 4w
w = 25.5 m
And l = w + 5 = 30.5 m