Problema Solution
A model rocket is launched with an initial upward velocity of 235ft/s . The rocket's height h (in feet) after t seconds is given by the following.
h=235t-16t^2
Find all values of for which the rocket's height is 151 feet.
Answer provided by our tutors
the rockets height is given by
h(t) = 235t-16t^2
we want to find all the values of t so that h(t) = 151 ft that is
we need to solve the quadratic equation
235t-16t^2 = 151
to see the step by step solution click here:
t1 = 0.67 s
t2 = 14.01 s
0.67 s and 14.01 s after the launching the rocket will be at 151 ft height.