Problema Solution
Jason and Tyler both live 13 miles from school. If one drives at 37 miles per hour and one at 52 miiles per hour what is their time difference
Answer provided by our tutors
let
v1 = 37 mph the average speed of Jason
v2 = 52 mph the avergae speed of Tyler
t1 = the time Jason travels
t2 = the time Tyler travels
d = 13 miles the distance they both pass
we need to find the time difference that is t1 - t2
the average speed = distance / time => time = distance / avg. speed thus we have
t1 = d/v1
t2 = d/v2
t1 - t2 = d/v1 - d/v2 = d(1/v1 - 1/v2) = 13(1/37 - 1/52)
t1 - t2 = 195/1924 hours = 195*60/1924 min = 6 min 5 sec
their time difference is 6 minutes and 5 seconds.