B747 aircraft flew 6 hours with the...

Problema Solution

B747 aircraft flew 6 hours with the wind. The return trip tool 7 hours against the wind. If the speed of the plane in still air is 13 times the speed of the wind, find the wind speed and speed of the plane in still air. Set up the equation first the solve.

Answer provided by our tutors

let

t1 = 6 hours is the time traveled with the wind

t2 = 7 hours is the time traveled against the wind

v = the speed of the wind in still air

w = the wind speed

d = the distance traveled in one direction

the speed of the plane in still air is 13 times the speed of the wind

v = 13w

the speed of the aircraft when traveling with the wind is: v + w

the speed of the aircraft when traveling against the wind is: v - w

since speed=distance/time => distance=speed*time

(v + w)*t1 = d = (v - w)*t2

(v + w)*6 = (v - w)7

we plug v=13w in the above equation and get

(13w + w)6 = (13w - w)7

14*6w = 12*7w

84w = 84w identity

There is no unique solution => any speed:wind = v:w = 13:1 relationship will work.

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