Problema Solution
A cyclist goes from one village to another at 28 km/h. He returns at 24 km/h. If the return journey takes two hours longer than the outward journey, what is the distance between the villages.
Answer provided by our tutors
let
v1 = 28 km/h the outward speed
v2 = 24 km/h the return speed
t1 = the time of the outward journey
t2 = the time of the return journey
t2 = t1 + 2
since speed = distance/time => distance = speed*time
v1*t1 = v2*t2
28*t1 = 24*t2
by solving the system of equations
t2 = t1 + 2
28*t1 = 24*t2
we find
click here to see the step by step solution of the system
t1 = 12 h
t2 = 14 h
distance = v1*t1 = 28*12 = 336 km
the distance between the villages is 336 kilometers.