Problema Solution

The perimeter of a rectangular field is 360 yd. The length is 80 yd longer than the width. find the dimensions.

The smaller od the two sides is ___yd.

The larger od the two sides is ____yd.

Answer provided by our tutors

let


w = the width of the field

l = the length of the field


the perimeter of a rectangular field is 360 yd


w + l = 360


the length is 80 yd longer than the width


l = 80 + w


by solving the system of equations


w + l = 360

l = 80 + w


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we find


l = 220 yd


w = 140 yd


The smaller od the two sides is 140 yd.

The larger od the two sides is 220 yd.