Problema Solution
How many gallons of a 16% salt solution must be mixed with 40 gallons of a 24% solution to obtain a 20% solution?
Answer provided by our tutors
let
x = the gallons of 16% salt solution
x is mixed with 40 gallons thus the new 20% solution mix will weight x + 40 gallons
the salt percentage will be
16% of x + 24% of 40 = 20% of (x + 40)
0.16x + 0.24*40 = 0.20(x + 40)
by simplifying and solving the equation we find
x = 40 gallons
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40 gallons of 16% salt solution must be used in the mix.