Problema Solution
The perimeter of a rectangle is 40 ft, the length is 8ft longer than the width. Find the dimensions.
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
the perimeter of a rectangle is 40 ft
2(l + w) = 40
the length is 8ft longer than the width
l = 8 + w
by solving the system of equations
2(l + w) = 40
l = 8 + w
we find the dimensions
l = 14 ft
w = 6 ft
click here to see the step by step solution of the system
the dimensions of the rectangle are 14 ft and 6 ft.