Problema Solution
15. A restaurant has one type of lemonade that is 12% sugar and another that is 7% sugar. How many gallons of each type does the restaurant need to make 20 gallons of a lemonade mixture that is 10% sugar?
Answer provided by our tutors
let
x = gallons of 12% sugar lemonade
y = gallons of 7% sugar lemonade
we need to make 20 gallons of a lemonade mixture that is 10% sugar thus we have
x + y = 20
12% sugar of x + 7% sugar of y = 10% sugar of the 20 gallons mix
0.12x + 0.07y = 0.10*20
by solving the system of equations
x + y = 20
0.12x + 0.07y = 0.10*20
we find
x = 12 gallons
y = 8 gallons
to see the step by step solution of the system of equations click here
the restaurant needs to mix 12 gallons of 12% sugar lemonade with 8 gallons of 7% sugar lemonade to obtain 10 gallons of 10% sugar lemonade.