Problema Solution
Use the like bases property to solve the equation: (1/3)^(n-7)=3^(6n-9)
Answer provided by our tutors
(1/3)^(n-7)=3^(6n-9)
(3^(-1))^(n-7) = 3^(6n-9)
3^((-1)(n-7)) = 3^(6n-9)
3^(7-n) = 3^(6n-9) multiply both sides by (3^(6n-9))^(-1)
(3^(7-n)) *(3^(6n-9))^(-1) = 1
(3^(7-n)) *(3^((-1)*(6n-9))) = 1
3^((7-n) + ((-1)(6n-9)) = 3^0
(7-n) - (6n-9) = 3^0
7 - n - 6n + 9 = 3^0
-7n + 16 = 3^0
7n = 16
n = 16/7