Problema Solution
three lockers are numbered consecutively (n, n+1, n+2) in such a way that the sum of the first and last locker is the same as twice the middle locker number. what are the locker nubers
Answer provided by our tutors
The lockers are numbered n, n+1, and n+2.
The question states that the sum of the first and last locker is the same as twice the middle locker number. Therefore:
n + (n+2) = 2 (n+1)
using algebra...
2n + 2 = 2n + 2
2n = 2n
n = n
This essentially means that any value for n satisfies the equation, because a number is always equal to itself. Therefore, it is impossible to determine the locker numbers given the information in the problem.