Problema Solution
A train leaves a station and travel at 80km. two hours later, a second train leaves on a parallel track and travels at 110 km in the same direction. how far from the station will they meet?
Answer provided by our tutors
let
v1 = 80 km/h the speed of the first train
t1 = the time that the first train traveled
v2 = 110 km/h the speed of the second train
t2 = the time that the second train traveled
2 hours later the second trains starts the travel thus
t1 = t2 + 2
since speed = distance/time => distance = speed*time
d = v1*t1 = v2*t2, where d is the distance traveled from the station
80t1 = 110t2
by solving the system of equations
t1 = t2 + 2
80t1 = 110t2
we find
t1 = 22/3 hours
t2 = 16/3 hours
click here to see the step by step solution of the system
d = t1*v1 = (22/3)*80 = 586.67 km
they will meet 586.67 km from the station.