Problema Solution
The length of a rectangle is six time its width. If the perimeter of the rectangle is 140ft, find it's area?
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
A = l*w the area of the rectangle
P = 2(l + w) the perimeter of the rectangle
the length of a rectangle is six time its width
l = 6w
the perimeter of the rectangle is 140ft
2(l + w) = 140
by solving the system of equations
l = 6w
2(l + w) = 140
we find
l = 60 ft
w = 10 ft
click here to see the step by step solution of the system of equations
A = l*w
A = 60*10 = 600 ft^2
the area if the rectangle is 600 ft^2.